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LinkJan 30, '09 2:52 AM
by fernando for everyone
Link: http://ferman.topcities.com/atom_models.html

New atom model and Cosmos model (1975) where the Cosmos is structured through the fouth dimension of space.
This way atoms, stars, etc. have the same structure and relative measures, and where two unique forces structure the Universe, gravity and magnetic force.

danbirchall wrote on Jan 30, '09
Hmmm... you might want to post this in the Physics group, too, since it looks like it deals mostly with particle physics, then with cosmological physics, and not so much with most aspects of astronomy. But thanks for posting it... now my brain hurts. :)
drxzero wrote on Jan 30, '09
Wow ... amazing !! Thanks a lot, good job

Regards,

Dr. Zero
fermancebo wrote on Jan 31, '09
Thank you friends.
I post here (in astronomy) my atomic model because this is also a star and cosmic model due to be a Unity theory.
This way, my theory bets and explains the following main questions:

1.- The number of planets and their distances from the nucleus depend on the quantity of star’s mass.
This way, any star that has the same mass than ours, the Earth, has to be the some number of planets and situated to similar distances.
The formula relative to mass and planets situation is given in this page.

2.- The Big-bang is not a unique event in the Cosmos. Continuous Big-bangs are producing constantly in el Cosmos and in all its levels.
--At atomic levels the Big-bangs are the explosion of de big atoms are uranium.
--At star levels the Big-bangs are the explosion of supernovas.
--At supra-star levels (our Big-bang) the explosion of accumulation of stars ( <10E57 ), matter and cosmic dust give in many places of the Cosmos Big-bangs similar to ours.
So, matter, atoms, stars, etc. was created infinitely before the Bing-bang.

3.- Black holes don’t exist.
In the centre of the galaxies what exists is a semi-compact nucleus of stars, which can be measured as a body of great mass.
If in the centre of galaxies black holes would exist, then the galaxy stars will be captured y converted into black holes.

Etc.
Thank to all you.
Fernando.


danbirchall wrote on Jan 31, '09
The number of planets and their distances from the nucleus depend on the quantity of star’s mass.
This way, any star that has the same mass than ours, the Earth, has to be the some number of planets and situated to similar distances.
This will probably be the easiest of your assertions to test scientifically, since astronomers have started detecting planets around other stars in the last 15-20 years. I don't know of any that have been able to identify an entire planetary system around a one-solar-mass star yet, though - probably in a few more years, you will know whether you are right.

You don't seem to leave much room for entropy here, though.
fermancebo wrote on Feb 1, '09
Well, as for my theory the orbits of planets are determinate and fixed by the magnetic fields of the each star.
Say, the magnetic fields of any star creates several stationary orbits around it, on which, the planets find a more equilibrated places where they can be situated better.
In this, case the stationary magnetic orbits created by the star nucleus around it can be aligned with the own magnetic fields of the planets.
And as it is logical, when more mass of the star, bigger magnetic fields and more stationary orbits where fix planets.
For this reason the mass of stars is responsible of the quantity of planets around it.
So in star, the random situation of planets around the stars is no contemplated for my theory.

On the other hand, in binary, three, four, etc. stars, these are ordered by their magnetic fields. And much more, they can even interchange planets if were convenient for their total magnetic balance.
This way, the magnetic fields of the stars are very important for the conformation of the same ones.
Of course, this is my viewpoint and the possibility that my theory propose. The time will say.
Thank you.
Fernando .

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